2x^2+24x-72=-94

Solution for 2x^2+24x-72=-94 equation:

2x^2+24x-72=-94

We move all terms to the left:

2x^2+24x-72-(-94)=0

We add all the numbers together, and all the variables

2x^2+24x+22=0

a = 2; b = 24; c = +22;
Δ = b2-4ac
Δ = 242-4·2·22
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-20}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+20}{2*2}=\frac{-4}{4}
=-1
$